Python Program to get a list of square root of all odd numbers between 1 to 20 Using List Comprehension

In this article, we will be solving a very interesting question based on List Comprehension. According to the question we have to create a list of square root of all odd numbers between 1 to 20 using list comprehension only.

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Question - Write a Python Program to get a list of square root of all odd numbers between 1 to 20 Using List Comprehension

Logic and Explanation

Question - Write a Python Program to get a list of square root of all odd numbers between 1 to 20 Using List Comprehension

Python Program to get a list of square root of all odd numbers between 1 to 20 Using List Comprehension - In this program we have to use list comprehension only. First thing we will be doing to to create a for loop from 1 to 20. Then, we will apply a simple if condition to check whether the number in the loop is odd or not.

For this we check if the remainder on dividing the number with 2 is not equal to zero, then the number is the odd number. In this way we separated the odd number and now we add to the list i raised to power 0.5 which means square root.

Also Read - Python Program to Separate Numbers and Letters in a String

Here's the code for the same.

L = [i ** 0.5 for i in range(1,21) if i%2 != 0]
print(L)

One more can be to use the math module of the Python. From this math module, we can use the built-in function sqrt() to find the square root the odd number. You can check the code for this also below.

import math
L = [math.sqrt(i) for i in range(1,21) if i%2 != 0]
print(L)

Output - 

[1.0, 1.7320508075688772, 2.23606797749979, 2.6457513110645907, 3.0, 3.3166247903554, 3.605551275463989, 3.872983346207417, 4.123105625617661, 4.358898943540674]

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Enjoy Coding!!!

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